Ngô Quốc Anh

June 5, 2008

An application of Chebyshev integral inequality

Filed under: Các Bài Tập Nhỏ, Giải Tích 2 — Ngô Quốc Anh @ 5:06

From http://mathworld.wolfram.com/ChebyshevIntegralInequality.html by setting , , , f_1 (x) = f_2(x) = x^\frac {x}{2} we get

\sqrt {\int^2_1x^x\,dx} \geq \int^2_1\sqrt {x^x}\,dx

It’s easy to prove that is nonnegative and monotonic increasing.

Leave a Comment »

No comments yet.

RSS feed for comments on this post. TrackBack URI

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s

Create a free website or blog at WordPress.com.

%d bloggers like this: